A) highest
B) lowest
C) mean
D) zero
Correct Answer: A
Solution :
Let v be the velocity of electron, m the mass, r the radius and h the Planck's constant. Then velocity of electron in permitted orbit n is \[v=\frac{Z{{e}^{2}}}{2\,h{{\varepsilon }_{0}}}\frac{1}{n}\] Where, Z is atomic number \[\Rightarrow \] \[v\propto \frac{1}{n}\] This shows that the velocity of electron is maximum in the lowest orbit and goes on decreasing in higher orbits.You need to login to perform this action.
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