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AFMC AFMC Solved Paper-2002

  • question_answer
    The kinetic energy of 14 g of nitrogen gas at \[\text{127}{{\,}^{o}}\text{C}\]is [gas constant = 8.31 J/K/mol]

    A)  4.4673 kJ            

    B) 3.857 kJ

    C) 2.493 kJ                               

    D) 1.857 kJ

    Correct Answer: C

    Solution :

    \[KE=\frac{3}{2}nRT=\frac{3}{2}.\frac{W}{M}.RT\](Mol. mass of N = 28) \[=\frac{3}{2}\times \frac{14}{28}\times 8.31\times 400\] \[[T=273+127=400K]\] \[=2493\,\,J\]or 2.493 kJ


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