AFMC AFMC Solved Paper-2002

  • question_answer
    A gas diffuses four times as quickly as oxygen. The molecular weight of gas is :

    A)

    B) 4

    C) 8                                             

    D) 16

    Correct Answer: A

    Solution :

    According to rate of effusion or diffusion \[\frac{{{r}_{{{o}_{2}}}}}{{{r}_{x}}}=\sqrt{\frac{{{M}_{x}}}{{{M}_{{{o}_{2}}}}}}\]                 \[\left[ {{r}_{x}}=4{{r}_{{{o}_{2}}}} \right]\] Molecular mass of oxygen = 32 \[\frac{{{r}_{{{o}_{2}}}}}{4{{r}_{{{o}_{2}}}}}=\sqrt{\frac{{{M}_{x}}}{32}}\] \[{{M}_{x}}=2\]                               


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