A) 0.02 C
B) 0.04 C
C) 0.08 C
D) 0.01 C
Correct Answer: A
Solution :
Key Idea: Maximum flux is linked with coil when its plane is perpendicular to magnetic field. The flux \[(o|)\]linked with coil is \[o|=NAB\,cos\theta \] When plane of coil is perpendicular to field \[\theta ={{90}^{o}}\] \[\therefore \] \[\text{o }\!\!|\!\!\text{ }=\text{NAB}\] Change in flux when rotating the coil by \[{{180}^{o}}\]is given by \[d\text{o }\!\!|\!\!\text{ =NAB-(-NAB) = 2 NAB}\] Also, from Faraday's law of electromagnetic induction, we have \[e=-\frac{d\text{o}|}{dt}\]where, \[e=IR,\,I\]is current and R is resistance. \[\therefore \] \[IR=\frac{d\text{o }\!\!|\!\!\text{ }}{dt}\] \[\therefore \] Charge \[Idt=\text{o }\!\!|\!\!\text{ /R}\] or \[\text{Charge}=\frac{2\,NAB}{R}\] \[\therefore \] Induced charge \[=\frac{2\times 100\times 0.001\times 1}{10}\]You need to login to perform this action.
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