A) \[L\,mo{{l}^{-1}}\,tim{{e}^{-1}}\]
B) \[mol\,{{L}^{-1}}\,\] time
C) \[tim{{e}^{-1}}\]
D) none of the above
Correct Answer: C
Solution :
Unit of \[k=\frac{{{(mol/L)}^{1-n}}}{\sec }\] n = order of reaction For zero order reaction n = 0 Unit of \[k=mol\,{{L}^{-1}}{{s}^{-1}}\] For first order reaction n = 1 Unit of \[k=\frac{{{(mol\,{{L}^{-1}})}^{1-n}}}{\sec }\] \[={{s}^{-1}}\]or \[tim{{e}^{-1}}\]You need to login to perform this action.
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