A) +1
B) -1
C) +2
D) + 3
Correct Answer: A
Solution :
Let the oxidation number of phosphorus in \[Ba({{H}_{2}}P{{O}_{2}})\]is \[x\] \[\therefore \] \[Ba{{({{H}_{2}}P{{O}_{2}})}_{2}}\] \[=(+2)+(1\times 4)+(x+2)+(-2\times 4)=0\] \[2+4+2x+(-8)=0\]\[x=+1\]You need to login to perform this action.
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