A) \[[M{{L}^{-3}}{{T}^{-2}}]\]
B) \[[M{{L}^{-2}}{{T}^{-1}}]\]
C) \[[M{{L}^{2}}{{T}^{-3}}]\]
D) \[[M{{L}^{2}}{{T}^{-1}}]\]
Correct Answer: D
Solution :
Key Idea: Writing a relation for Plancks constant and substitute dimensions for corresponding physical quantities. The energy (E) of a photon of light is given by E = hv (v is frequency) \[\therefore \] \[\text{Diamensions of h =}\frac{\text{dimensions of energy E}}{\text{dimensions of frequency v}}\] \[=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{T}^{-1}}]}=[M{{L}^{2}}{{T}^{-1}}]\]
You need to login to perform this action.
You will be redirected in
3 sec
