A) greater than 1200 m
B) less than 1200 m
C) 1400 m
D) 1500 m
Correct Answer: A
Solution :
As give in question \[OA=400\,m\](due north) \[AB=300\,m\](due south) \[\therefore \] \[OB=OA-AB\] \[=400-300=100\] Also \[BC=1200\,m\](upwards) In right triangle \[\Delta OBC,\] \[O{{C}^{2}}=O{{B}^{2}}+B{{C}^{2}}\] \[\therefore \] Displacement \[OC=\sqrt{O{{B}^{2}}+B{{C}^{2}}}\] \[=\sqrt{{{(100)}^{2}}+{{(1200)}^{2}}}\] \[=\sqrt{10000+1440000}\] \[=\sqrt{1450000}\] \[=1204\,m>\,1200\,m\] Hence, net displacement is greater than 1200 m.You need to login to perform this action.
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