AFMC AFMC Solved Paper-2004

  • question_answer
    What are the units of K = 1/4\[\pi {{\varepsilon }_{0}}?\]

    A) C2N-1m-2                              

    B) Nm2C-2

    C) Nm2C2                                  

    D) Unit less

    Correct Answer: B

    Solution :

    From Coulomb's law two stationary point charges \[{{q}_{1}}\]and \[{{q}_{2}}\]attract or repel each other with a force F which is directly proportional to the product of the charges and inversely proportional to the square of distance  between them, i.e.,            \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[\therefore \]    \[K=\frac{1}{4\pi {{\varepsilon }_{0}}}=\frac{F{{r}^{2}}}{{{q}^{2}}}\]              (if \[{{q}_{1}}={{q}_{2}}=q\]) Hence, unit of   \[K=\frac{N{{m}^{2}}}{{{C}^{2}}}\]                   \[=N{{m}^{2}}{{C}^{-2}}\]         


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