A) 25%
B) 75%
C) 50%
D) 100%
Correct Answer: C
Solution :
Since ball is at a specific height it possess potential energy = mgh where m is mass, g is gravity and h is height. Initial energy of ball \[=mg{{h}_{1}}\] \[=20\,mg\] Final energy of ball \[=mg{{h}_{2}}\] \[=10\,mg\] Therefore, the loss in energy \[=\frac{\text{initial energy}-\text{final energy}}{\text{initial energy}}\times 100\] \[=\frac{20mg-10mg}{20mg}\times 100\]\[=50%\]
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