A) \[80{}^\circ C\]
B) \[40{}^\circ C\]
C) \[50{}^\circ C\]
D) \[90{}^\circ C\]
Correct Answer: B
Solution :
Key Idea: Fall in temperature in Centigrade thermometer = Initial temperature of boiling water -fall in temperature. The relation between Centigrade \[{{\,}^{o}}C\]scale of temperature and Fahrenheit \[{{\,}^{o}}F\]scale is \[\frac{C}{5}=\frac{F-32}{9}\] Given, Fahrenheit \[F={{140}^{o}}F\] \[\therefore \] \[\frac{C}{5}=\frac{140-32}{9}=\frac{108}{9}=12\] \[\Rightarrow \] \[C=12\times 54=60{{\,}^{o}}C\] \[\therefore \] Fall in temperature in centigrade scale = initial temperature - full in temperature \[=100{{\,}^{o}}C-60{{\,}^{o}}C=40{{\,}^{o}}C\]
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