A) ethyl formic acid
B) ethyl carboxylic acid
C) ethane methanoic acid
D) propanoic acid
Correct Answer: D
Solution :
For carboxylic acid \[-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-O-H\] General name \[Alkane-e+ioc\,acid\to alanoic\,acid\] \[\overset{3}{\mathop{C}}\,{{H}_{3}}{{\overset{2}{\mathop{C}}\,}_{2}}{{H}_{2}}\overset{1}{\mathop{C}}\,OOH\] IUPAC = Propanoic acid
You need to login to perform this action.
You will be redirected in
3 sec
