A) 2 mm
B) 4 mm
C) 6 mm
D) 8 mm
Correct Answer: D
Solution :
\[\text{Refractiv index ( }\!\!\mu\!\!\text{ ) = }\frac{\text{Real}\,\text{depth}}{\text{Apparent}\,\text{depth}}\] \[\mu =\frac{12}{\text{Apparent depth}}\] \[1.5=\frac{12}{\text{Apparent depth}}\] \[\Rightarrow \] \[\text{Apparent}\,\text{depth =}\frac{\text{12}}{\text{1}\text{.5}}\text{= 8 mm}\]You need to login to perform this action.
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