A) 100 Hz
B) 50 Hz
C) 250 Hz
D) 150 Hz
Correct Answer: C
Solution :
Key Idea: A closed pipe produces only odd harmonics ie., 1: 3 : 5 : 7............... If v is the velocity of sound in air, n is the frequency of note emitted and I is the length of pipe then \[n=\frac{v}{4l}\] Also a closed pipe produces only odd harmonics i.e., 1:3:5:7.......... Hence, second overtone or fifth harmonic frequency is \[=\frac{5v}{4l}=5\times 50=250\,\text{Hz}\]You need to login to perform this action.
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