A) 2.4 L
B) 2.24 L
C) 44 L
D) 22.4 L
Correct Answer: B
Solution :
1 mole of a substance = 2Z4 L at STP 1 mole of \[C{{O}_{2}}=44\,g\] \[44\,g=22.4\,L\] \[1\,g=\frac{22.4\,L}{44}\] \[4.4\,g=\frac{22.4}{44}\times \frac{4.4}{10}=2.24\,L\]You need to login to perform this action.
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