A) 0.25 N
B) 1 N
C) 2 N
D) 7 N
Correct Answer: B
Solution :
Molarity \[({{M}_{1}})\]of \[{{H}_{2}}S{{O}_{4}}=5\,M\] \[Normality\,({{N}_{1}})=molarity\times basicity\] \[=5\times 2=10N\] \[{{V}_{1}}=1\,L\] \[{{V}_{2}}=1\,0\,L\] According to principle of dilution number of equivalent before dilution = number of equivalent after dilution \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[10\times 1={{N}_{2}}\times 10\] \[{{N}_{2}}=1\,N\]You need to login to perform this action.
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