A) Shrinks
B) Disappear
C) Unchanged
D) Enlarged
Correct Answer: A
Solution :
Key Idea: In water, wavelength of light decreases by a factor \[\mu ,\]the refractive index of water. In Young's double slit experiment, let screen is placed at a distance D, d is the distance between coherent sources. The fringe width is given by \[W=\frac{D\lambda }{d}\]where, \[\lambda \] is wavelength of light used. When the whole setup is dipped in water, wavelength is \[{{\lambda }_{w}}=\frac{{{\lambda }_{a}}}{\mu },\] hence, it decreases. Therefore, fringe width decreases and hence, fringe pattern shrinks.You need to login to perform this action.
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