A) gravitational head, pressure head and velocity head
B) gravity, gravitational head and velocity head
C) pressure head. gravitational head and velocity head
D) gravity, pressure and velocity head
Correct Answer: C
Solution :
According to Bernoulli's theorem, in case of steady flow of incompressible and non-viscous liquid through a tube of non-uniform cross-section, the sum of the pressure, the potential energy per unit volume and the kinetic energy per unit volume is same at every point in the tube, i.e., \[p+\rho gh+\frac{1}{2}\rho {{v}^{2}}=\text{constant}\] Dividing this expression by \[\rho g,\]we have\[\frac{P}{\rho g}+\frac{{{v}^{2}}}{2g}+h=\text{cosntant}\] In this expression \[\frac{P}{\rho g}\]is called the 'pressure head', \[\frac{{{v}^{2}}}{2g}\] the 'velocity head' and h the 'gravitational head'.
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