A) 1
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
For fee, no. of atom at comer \[=\frac{1}{8}\times 8=1\] No. of atoms at face centre \[=\frac{1}{2}\times 6=3\] Total no. of atoms =1+3=4You need to login to perform this action.
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