A) \[3\times {{10}^{-23}}kg\,m{{s}^{-1}}\]
B) \[3.33\times {{10}^{22}}\,kg\,m{{s}^{-1}}\]
C) \[1.452\times {{10}^{-44}}\,kg\,m{{s}^{-1}}\]
D) \[6.89\times {{10}^{43}}\,kg\,m{{s}^{-1}}\]
Correct Answer: A
Solution :
According to de-Broglie, the wavelength \[(\lambda )\] associated with momentum (p) of a particle given by following relation \[\lambda =\frac{h}{p}\] Here, h = Planck?s constant \[p=\frac{h}{\lambda }=\frac{6.6\times {{10}^{-34}}}{2.5\times {{10}^{-11}}}\] \[=3\times {{10}^{-23}}\,kg\,m{{s}^{-1}}\]
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