A) \[_{0}{{n}^{1}}\]
B) \[_{-1}{{e}^{0}}\]
C) \[_{1}{{H}^{1}}\]
D) \[_{1}{{H}^{2}}\]
Correct Answer: C
Solution :
\[_{13}A{{l}^{27}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{14}}{{P}^{30}}{{+}_{1}}{{H}^{1}}\] Proton \[{{(}_{1}}{{H}^{1}})\]is emitted in this reaction.
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