A) lead dioxide dissolves
B) sulphuric acid is regenerated
C) the lead electrode becomes coated with lead sulphate
D) the amount of sulphuric acid decrease
Correct Answer: B
Solution :
During the charging of a lead storage battery, the reaction at the anode and cathode are Anode: \[PbS{{O}_{4}}+2{{e}^{-}}\,\xrightarrow{{}}Pb+SO_{4}^{2-}\] Cathode: \[PbS{{O}_{4}}+2{{H}_{2}}O\] \[\xrightarrow{{}}Pb{{O}_{2}}+4{{H}^{+}}+SO_{4}^{2-}+{{e}^{-}}\] In both the reactions \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]is regenerated.
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