A) \[[Ne]\text{ }3{{s}^{2}}\text{ }3{{p}^{1}}\]
B) \[\text{ }\!\![\!\!\text{ }Ne\text{ }\!\!]\!\!\text{ }3{{s}^{2}}3{{p}^{2}}\]
C) \[\text{ }\!\![\!\!\text{ }Ne\text{ }\!\!]\!\!\text{ }3{{s}^{2}}3{{p}^{2}}\]
D) \[\text{ }\!\![\!\!\text{ }Ne\text{ }\!\!]\!\!\text{ }3{{s}^{2}}3{{p}^{4}}\]
Correct Answer: B
Solution :
Elements having half-filled or fully filled orbitals are more stable. Hence, much energy is required to remove an electron from the outermost orbit. So, the element with \[\text{ }\!\![\!\!\text{ Ne }\!\!]\!\!\text{ 3}{{\text{s}}^{\text{2}}}\text{ 3}{{\text{p}}^{\text{3}}}\] configuration has highest ionisation energy.You need to login to perform this action.
You will be redirected in
3 sec