AFMC AFMC Solved Paper-2009

  • question_answer
    If elements with principal quantum number n > 4 were not allowed in nature, then the number of possible elements would be

    A) 32                                          

    B) 60

    C) 18                                          

    D) 4

    Correct Answer: B

    Solution :

    If all the elements having n > 4 are removed the number of elements that will be present in the periodic table are calculated as : n = 1 represents K shell and the number of elements having K shell =2            \[[2{{n}^{2}}]\] n = 2 represents L shell and the number of elements having L shell = 8 n = 3 represents M shell and the number of elements having M shell =18 n = 4 represents N shell and the number of elements having N shell =32 So the total number of elements having n < 5 are2 + 8 + 18 + 32 = 60


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