AFMC AFMC Solved Paper-2009

  • question_answer
    The average power dissipation in pure inductance is

    A) \[\frac{1}{2}L{{I}^{2}}\]                                                

    B)  \[2L{{I}^{2}}\]

    C) \[\frac{1}{4}L{{I}^{2}}\]                                

    D) zero

    Correct Answer: D

    Solution :

    The average of instantaneous power in an AC circuit over a full cycle is called average power. Ifs unit is watt. \[{{P}_{av}}={{V}_{rms}}{{I}_{rms}}\cos \text{o }\!\!|\!\!\text{ }\] In a pure inductance, phase difference between voltage and current\[\text{o }\!\!|\!\!\text{ = 9}{{\text{0}}^{o}}.\] Power factor\[\cos \,o|\,=0\] \[\therefore \]    Power P = 0


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