AFMC AFMC Solved Paper-2009

  • question_answer
    Two equal and opposite charge (+ q and - q) are situated at x distance from each other, the value of potential at very far point will depend upon

    A) only on q                            

    B) only on x

    C) on qx                                    

    D) on \[\frac{q}{x}\]

    Correct Answer: C

    Solution :

    Electric potential due to electric dipole at axial line \[{{E}_{axial}}=\frac{k(2qx)}{({{r}^{2}}-{{x}^{2}})}\]where r is the distance of observation point from centre of dipole. For general point \[{{E}_{q}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2qx\cos \theta }{{{r}^{2}}}\] So, the value of potential depends on \[qx.\]


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