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AFMC AFMC Solved Paper-2009

  • question_answer
    A car of mass m is moving with momentum p. If\[\mu \] be the coefficient of friction between the tyres and the road, what will be stopping distance due to friction alone?

    A) \[\frac{{{p}^{2}}}{2\mu g}\]                                       

    B) \[\frac{{{p}^{2}}}{2m\mu g}\]

    C) \[\frac{{{p}^{2}}}{2{{m}^{2}}\mu g}\]                    

    D) \[\frac{{{p}^{2}}}{2mg}\]

    Correct Answer: C

    Solution :

    If the car stops after covering distance s, then \[F\times s=\frac{{{p}^{2}}}{2m}\] Where        \[F=friction\] Now         \[F=\mu mg\] So, \[\mu mg\times s=\frac{{{p}^{2}}}{2m}\]\[\Rightarrow \]    \[s=\frac{{{p}^{2}}}{2\mu {{m}^{2}}g}\]


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