A) Ethyl amine
B) Methyl amine
C) Dimethyl amine
D) Phenyl amine
Correct Answer: C
Solution :
Carbylamine test is given by aliphatic as well as aromatic primary amines, ie, amines having \[-\text{N}{{\text{H}}_{\text{2}}}\]group. (a) \[\underset{\text{ethyl}\,\text{amine}}{\mathop{{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{N}{{\text{H}}_{\text{2}}}}}\,\] (b) \[\underset{\text{methyl}\,\text{amine}}{\mathop{\text{C}{{\text{H}}_{3}}\text{N}{{\text{H}}_{\text{2}}}}}\,\] (c) \[\underset{\text{dimethyl}\,\text{ }\,\text{amine}}{\mathop{{{\text{(C}{{\text{H}}_{\text{3}}}\text{)}}_{\text{2}}}\text{NH}}}\,\] (d)You need to login to perform this action.
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