A) \[ZnS{{O}_{4}}\]
B) \[FeS{{O}_{4}}\]
C) \[AgN{{O}_{3}}\]
D) \[HgC{{l}_{2}}\]
Correct Answer: A
Solution :
On adding sodium hydroxide to the \[\text{ZnS}{{\text{O}}_{\text{4}}}\]solution, first the white precipitate of zinc hydroxide is obtained, which dissolves in excess of NaOH due to the formation of sodium zincate. \[ZnS{{O}_{4}}+NaOH\xrightarrow{{}}\underset{\text{white}\,\text{ppt}}{\mathop{Zn{{(OH)}_{2}}}}\,\downarrow +N{{a}_{2}}S{{O}_{4}}\] \[Zn{{(OH)}_{2}}+2NaOH\xrightarrow{{}}\underset{\begin{smallmatrix} \text{sodium} \\ \text{zincate} \end{smallmatrix}}{\mathop{N{{a}_{2}}Zn{{O}_{2}}}}\,+2{{H}_{2}}O\]
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