A) \[HCl\]
B) \[C{{l}_{2}}\]
C) \[PC{{l}_{5}}\]
D) \[aq\text{ }NaHS{{O}_{3}}\]
Correct Answer: A
Solution :
\[\text{HCl}\]is a strong inorganic acid, hence it does not react with ethanal whereas with other given reagents, it reacts in the following manner : \[\underset{\text{ethanal}}{\mathop{C{{H}_{3}}CHO}}\,+C{{l}_{2}}\xrightarrow{{}}\underset{\text{chloral}}{\mathop{CC{{l}_{3}}CHO}}\,\] \[C{{H}_{3}}CHO+PC{{l}_{5}}\xrightarrow{{}}C{{H}_{3}}CHC{{l}_{2}}\] \[C{{H}_{3}}CHO+NaHS{{O}_{3}}\xrightarrow{{}}C{{H}_{3}}CH<_{S{{O}_{3}}Na}^{OH}\] \[C{{H}_{3}}CHO+HCl\xrightarrow{{}}\text{No reaction}\text{.}\]
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