AFMC AFMC Solved Paper-2009

  • question_answer
    If the solubility of calcium fluoride in pure water is \[x\]mol/L, its solubility product is

    A) \[\sqrt{2}x\]                      

    B) \[2{{x}^{2}}\]

    C) \[4{{x}^{3}}\]                                    

    D) \[{{x}^{2}}\]

    Correct Answer: C

    Solution :

    \[\underset{x}{\mathop{Ca{{F}_{2}}}}\,\rightleftharpoons \underset{x}{\mathop{C{{a}^{2+}}}}\,+\underset{2x}{\mathop{2{{F}^{-}}}}\,\] \[{{K}_{sp}}=[C{{a}^{2+}}]{{[2{{F}^{-}}]}^{2}}\] \[=(x){{(2x)}^{2}}=4{{x}^{2}}\]


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