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AFMC AFMC Solved Paper-2009

  • question_answer
    The molarity of a solution containing 5.0 g of \[\text{NaOH}\] in 250 mL solution is

    A) 0.1                                         

    B) 0.5

    C) 1.0                                         

    D) 2.0

    Correct Answer: B

    Solution :

    \[\text{Molarity = }\frac{\text{number of moles of solute}}{\text{volume of solution}}\] \[=\frac{5\times 1000}{40\times 250}\]  [ \[\because \]moles of \[\text{NaOH}\] \[=\frac{5}{40}\]] \[=0.5\,\text{M}\]


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