A) \[\text{M}{{\text{n}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]
B) \[\text{Mn}{{\text{O}}_{\text{2}}}\]
C) \[\text{MnO}_{4}^{-}\]
D) \[MnO_{4}^{2-}\]
Correct Answer: B
Solution :
\[\overset{+2}{\mathop{Mn}}\,S{{O}_{4}}\xrightarrow{{}}\overset{+4}{\mathop{Mn}}\,{{O}_{2}}\] In this conversion, there is loss of two electrons, hence equivalent weight of MnS04 is the half of its molecular weight.
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