A) \[\frac{{{\tau }_{2}}}{{{\tau }_{1}}}\]
B) \[\frac{{{\tau }_{1}}}{{{\tau }_{2}}}\]
C) \[\frac{{{\tau }_{1}}+{{\tau }_{2}}}{{{\tau }_{1}}-{{\tau }_{2}}}\]
D) \[\frac{{{\tau }_{1}}-{{\tau }_{2}}}{{{\tau }_{1}}+{{\tau }_{2}}}\]
Correct Answer: B
Solution :
Torque, \[\tau =MB\sin \theta \] \[{{\tau }_{1}}=M{{B}_{1}}\sin {{90}^{o}}=M{{B}_{1}}\] \[{{\tau }_{2}}=M{{B}_{2}}\sin {{90}^{o}}=M{{B}_{2}}\] or \[\frac{M{{B}_{1}}}{M{{B}_{2}}}=\frac{{{\tau }_{1}}}{{{\tau }_{2}}}\] \[\therefore \] \[\frac{{{B}_{1}}}{{{B}_{2}}}=\frac{{{\tau }_{1}}}{{{\tau }_{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec