A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
Mass of oxygen in oxide \[=4-2.8\] \[=1.2\,g\] \[\text{Eq}\text{.wt}\text{.of}\,\text{metal =}\frac{\text{mass of metal}}{\text{mass of oxygen}}\text{ }\!\!\times\!\!\text{ 8}\] \[=\frac{2.8}{1.2}\times 8\] \[=18.67\] \[\text{Valency of metal =}\frac{\text{atomic wt}\text{. of metal}}{\text{eq}\text{.wt}\text{.of metal}}\] \[=\frac{56}{18.67}\](give) \[=3\]You need to login to perform this action.
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