A) \[45{}^\circ \]
B) \[60{}^\circ \]
C) \[90{}^\circ \]
D) \[120{}^\circ \]
Correct Answer: A
Solution :
Resultant, \[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] \[P\sqrt{10}=\sqrt{4{{P}^{2}}+2{{P}^{2}}+4\sqrt{2}{{P}^{2}}\cos \theta }\] \[\therefore \] \[\theta ={{45}^{o}}\]You need to login to perform this action.
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