A) 36 N
B) 12 N
C) 64 N
D) 24 N
Correct Answer: D
Solution :
Net force on the rod, \[f=32-20=12\,\text{N}\] Acceleration of rod \[=\frac{f}{m}=\frac{12}{3}=4\,m{{s}^{-2}}\] Equation of motion of 10 cm part is \[F-20=m\times a=1\times 4\] \[F=4+20=24\,N\] Similarly, Equation of motion 20 cm part is \[32-F=m'\,a=2\times 4\] \[F=32-8=24\,N\]You need to login to perform this action.
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