A) 0.2 A
B) 0.6 A
C) 1.2 A
D) 0.8 A
Correct Answer: A
Solution :
Induced emf \[e=-\frac{d\text{o }\!\!|\!\!\text{ }}{dt}=-\frac{d}{dt}(6{{t}^{2}}-5t+1)\]\[=12t+5\] \[e=-12(0.25)+5=2V\] Induced current, \[i=\frac{e}{R}=\frac{2}{10}=0.2A\]You need to login to perform this action.
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