A) 1.4 m/s
B) 14 m/s
C) 140 m/s
D) 0.14 m/s
Correct Answer: B
Solution :
\[\tan \theta =\frac{{{v}^{2}}}{rg}\] \[\Rightarrow \] \[\sqrt{rg\tan \theta }\] \[=\sqrt{200\times 10\times \tan {{5.71}^{o}}}\] \[=\sqrt{200\times 10\times 0.1}\] \[=14.14\,\,\,m/s\] \[=14\,\,m/s\]You need to login to perform this action.
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