A) 10 fold
B) \[\frac{1}{10}\] fold
C) 11 fold
D) \[\frac{1}{11}\] fold
Correct Answer: D
Solution :
Sensitivity of galvanometer is directly proportional to the current through it. When a shunt resistance S = (G /10) is applied to galvanometer of resistance G, then current through galvanometer, \[{{I}_{g}}\] can be written as \[{{I}_{g}}G=(I-{{I}_{g}})S\] \[=(I-{{I}_{g}})G/10\] or \[{{I}_{g}}=\frac{(I-{{I}_{g}})}{10}\] or \[{{I}_{g}}=\left( 1+\frac{1}{10} \right)=\frac{I}{10}\] \[\therefore \] \[{{I}_{g}}=\frac{1}{11}r\]
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