A) 2 : 1
B) 1 : 2
C) 1 : 1
D) 1 : 4
Correct Answer: C
Solution :
Frequency is given by \[v=\frac{1}{2l}\sqrt{\frac{T}{\mu }}\] \[\therefore \] First frequency, \[{{v}_{1}}=\frac{l}{2l}\sqrt{\frac{T}{\mu }}\] and second frequency, \[{{v}_{2}}=\frac{1}{4l}\sqrt{\frac{4T}{\mu }}\] \[\therefore \]Hence, the ratio of frequencies \[\frac{{{v}_{1}}}{{{v}_{2}}}=1:1\]
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