What is the equivalent weight of \[\text{SnC}{{\text{l}}_{\text{2}}}\]in the following reaction,\[\text{SnC}{{\text{l}}_{2}}\xrightarrow[{}]{{}}SnC{{l}_{4}}?\]
A)95
B)45
C)60
D)30
Correct Answer:
A
Solution :
Equivalent weight of \[SnC{{l}_{2}}=\frac{mol.wt.}{2}=\frac{190}{2}\] = 95