A) 0.2
B) 0.1
C) 0.5
D) 0.4
Correct Answer: B
Solution :
As \[n\lambda \] \[\therefore \] \[\lambda =\frac{v}{n}=\frac{300}{500}=\frac{3}{5}\text{m}\] Now, phase difference\[=\frac{2\pi }{\lambda }\times \] path difference \[\therefore \] \[{{60}^{o}}=\frac{2\pi }{\lambda }\times \]path difference or \[\frac{{{60}^{o}}\times \pi }{{{180}^{o}}}=\frac{2\pi \times 5}{3}\times \]path difference \[\therefore \] path difference \[=\frac{3\times 60\times \pi }{2\pi \times 5\times 180}=0.1\]
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