A) 10 cm
B) 10\[\sqrt{2}\] cm
C) 20 cm
D) 5\[\sqrt{2}\] cm
Correct Answer: B
Solution :
\[r=\frac{1}{B}\sqrt{\frac{2mV}{q}}\] \[\frac{{{r}_{\alpha }}}{{{\gamma }_{p}}}=\sqrt{\frac{{{m}_{\alpha }}}{{{m}_{p}}}}\sqrt{\frac{{{q}_{p}}}{{{q}_{\alpha }}}}\] \[\therefore \] \[{{r}_{\alpha }}=10\sqrt{2}\,cm\]
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