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AFMC AFMC Solved Paper-2011

  • question_answer
    A mass M is split into two pans m and (M - m), which are, then separated by a certain distance. The ratio m/ M which maximizes the gravitational force between the pans is

    A) 1 : 4                       

    B) 1 : 3

    C) 1 : 2                                       

    D) 1 : 1

    Correct Answer: C

    Solution :

    Force between the two parts at a distance \[x\] is given by \[F=\frac{GM(M-m)}{{{x}^{2}}}\] For maxima, \[\frac{dF}{dm}=\frac{G}{{{x}^{2}}}(M-2m)=0\]or \[\frac{m}{M}=\frac{1}{2}\]


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