A) mg
B) mg \[\left[ 1+{{\left( \frac{a}{L} \right)}^{2}} \right]\]
C) \[mg{{\left[ 1+\left( \frac{a}{2L} \right) \right]}^{2}}\]
D) \[mg{{\left[ 1+\left( \frac{a}{L} \right) \right]}^{2}}\]
Correct Answer: B
Solution :
\[T-mg\cos \theta =\frac{m{{v}^{2}}}{L}\]You need to login to perform this action.
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