A) 250 m
B) 250\[\sqrt{5}\] m
C) 1250 m
D) 2500 m
Correct Answer: D
Solution :
From the figure for sound travel ABC Given, Time for the echo \[=10\sqrt{5}s\] Velocity of the plane = 200 m/s Here, \[OC=200\times 5\sqrt{5}=2236\,m\] BC = velocity of sound \[\times 5\sqrt{5}\] \[\Rightarrow \]\[BC=300\times 5\sqrt{5}=3354\,m\] \[\therefore \] \[OB=\sqrt{B{{C}^{2}}-O{{C}^{2}}}\] \[OB=2500\,m\] The plane is 2500 m above the ground.You need to login to perform this action.
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