AFMC AFMC Solved Paper-2011

  • question_answer
    In the reaction \[{{H}_{2}}(g)+C{{l}_{2}}(g)2HCl(g)\]

    A) \[{{K}_{p}}\ne {{K}_{c}}\]                            

    B) \[{{K}_{p}}={{K}_{c}}\]

    C) \[{{K}_{p}}>{{K}_{c}}\]                  

    D) \[{{K}_{p}}<{{K}_{c}}\]

    Correct Answer: B

    Solution :

    \[{{H}_{2}}(g)+C{{l}_{2}}(g)2HCl(g)\] We know that, \[{{K}_{p}}={{K}_{c}}.{{(RT)}^{\Delta {{n}_{g}}}}\] \[\Delta {{n}_{g}}=\]number of moles of gaseous products - number of moles of gaseous reactants                    \[=2-2=0\]                      \[{{K}_{p}}={{K}_{c}}.R{{T}^{0}}\]                       \[{{K}_{p}}={{K}_{c}}\]


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