A) constant
B) t
C) \[\frac{1}{\sqrt{t}}\]
D) \[\sqrt{t}\]
Correct Answer: C
Solution :
K.E. = ct \[\frac{1}{2}m{{v}^{2}}=ct\] \[\frac{{{P}^{2}}}{2m}=ct\] \[P=\sqrt{2ctm}\] \[F=\frac{dP}{dt}=\sqrt{2cm}\frac{1}{2}\times \frac{1}{\sqrt{t}}\] \[F\propto \frac{1}{\sqrt{t}}.\]You need to login to perform this action.
You will be redirected in
3 sec