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JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    After absorbring a slowly moving neutron of Mass \[{{m}_{N}}\] (momentum \[\approx 0\]) a nucleus of mass M breaks into two nuclei of masses \[{{m}_{1}}\] and \[5{{m}_{1}}\]\[(6{{m}_{1}}=M+{{m}_{N}})\] respectively. If the de Broglic wavelength of the nucleus with mass \[{{m}_{1}}\]is \[\lambda ,\] the de Broglie wavelength of the nucleus will be:     AIEEE  Solved  Paper (Held On 11 May  2011)

    A) \[5\lambda \]

    B) \[\lambda /5\]

    C) \[\lambda \]

    D) \[25\lambda \]

    Correct Answer: C

    Solution :

                                    \[{{P}_{i}}=0\]                 \[{{P}_{f}}={{P}_{1}}+{{P}_{2}}\]                 \[{{P}_{i}}={{P}_{f}}\]                 \[0={{P}_{1}}+{{P}_{2}}\]                 \[({{P}_{1}}=-{{P}_{2}})\]                 \[{{\lambda }_{1}}=\frac{h}{{{P}_{1}}}\]                 \[{{\lambda }_{2}}=\frac{h}{{{P}_{2}}}\]                 \[|{{\lambda }_{1}}|=|{{\lambda }_{2}}|\]                 \[{{\lambda }_{1}}={{\lambda }_{2}}=\lambda .\]


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